Книга: C# 2008 Programmer

Using Constraints in a Generic Type

Using Constraints in a Generic Type

Using the MyStack class, suppose that you want to add a method called Find() that allows users to check if the stack contains a specific item. You implement the Find() method like this:

public class MyStack<T> {
 private T[] _elements;
 private int _pointer;
 public MyStack(int size) {
  _elements = new T[size];
  _pointer = 0;
 }
 public void Push(T item) {
  if (_pointer > _elements.Length - 1) {
   throw new Exception("Stack is full.");
  }
  _elements[_pointer] = item;
  _pointer++;
 }
 public T Pop() {
  _pointer--;
  if (_pointer < 0) {
   return default(T);
   //throw new Exception("Stack is empty.");
  }
  return _elements[_pointer];
 }
 public bool Find(T keyword) {
  bool found = false;
  for (int i=0; i<_pointer; i++) {
   if (_elements[i] == keyword) {
    found = true;
    break;
   }
  }
  return found;
 }
}

But the code will not compile. This is because of the statement:

if (_elements[i] == keyword)

That's because the compiler has no way of knowing if the actual type of item and keyword (type T) support this operator (see Figure 9-3). For example, you cannot by default compare two struct objects.


Figure 9-3 

A better way to resolve this problem is to apply constraint to the generic class so that only certain data types can be used. In this case, because you want to perform comparison in the Find() method, the data type used by the generic class must implement the IComparable<T> interface. This is enforced by using the where keyword:

public class MyStack<T> where T : IComparable<T> {
 private T[] _elements;
 private int _pointer;
 public MyStack(int size) {
  _elements = new T[size];
  _pointer = 0;
 }
 public void Push(T item) {
  if (_pointer > _elements.Length - 1) {
   throw new Exception("Stack is full.");
  }
  _elements[_pointer] = item;
  _pointer++;
 }
 public T Pop() {
  _pointer--;
  if (_pointer < 0) {
   return default(T);
  }
  return _elements[_pointer];
 }
 public bool Find(T keyword) {
  bool found = false;
  for (int i=0; i<_pointer; i++) {
   if (_elements[i].CompareTo(keyword) == 0) {
    found = true;
    break;
   }
  }
  return found;
 }
}

For the comparison, you use the CompareTo() method to compare two items of type T (which must implement the IComparable interface). The CompareTo() method returns 0 if the two objects are equal. You can now search for an item by using the Find() method:

MyStack<string> stack = new MyStack<string>(3);
stack.Push("A");
stack.Push("B");
stack.Push("C");
if (stack.Find("B")) Console.WriteLine("Contains B");

In this case, the code works because the string type implements the IComparable interface. Suppose that you have the following Employee class definition:

public class Employee {
 public string ID { get; set; }
 public string Name { get; set; }
}

When you try to use the MyStack class with the Employee class, you get an error:

MyStack<Employee> stack = new MyStack<Employee>(3); //---Error---

That's because the Employee class does not implement the IComparable<T> interface. To resolve this, simply implement the IComparable<Employee> interface in the Employee class and implement the CompareTo() method:

public class Employee : IComparable<Employee> {
 public string ID { get; set; }
 public string Name { get; set; }
 public int CompareTo(Employee obj) {
  return this.ID.CompareTo(obj.ID);
 }
}

You can now use the Employee class with the generic MyStack class:

MyStack<Employee> stack = new MyStack<Employee>(2);
stack.Push(new Employee() { ID = "123", Name = "John" });
stack.Push(new Employee() { ID = "456", Name = "Margaret" });
Employee e1 = new Employee() { ID = "123", Name = "John" };
if (stack.Find(e1))
 Console.WriteLine("Employee found.");

Specifying Multiple Constraints

You can specify multiple constraints in a generic type. For example, if you want the MyStack class to manipulate objects of type Employee and also implement the IComparable interface, you can declare the generic type as:

public class MyStack<T> where T : Employee, IComparable<T> {
 //...
}

Here, you are constraining that the MyStack class must use types derived from Employee and they must also implement the IComparable interface.

The base class constraint must always be specified first, before specifying the interface.

Assuming that you have the following Manager class deriving from the Employee class:

public class Manager : Employee, IComparable<Manager> {
 public int CompareTo(Manager obj) {
  return base.CompareTo(obj);
 }
}

The following statement is now valid:

MyStack<Manager> stackM = new MyStack<Manager>(3);

Multiple Type Parameter

So far you have seen only one type parameter used in a generic type, but you can have multiple type parameters. For example, the following MyDictionary class uses two generic type parameters — K and V:

public class MyDictionary<K, V> {
 //...
}

To apply constraints on multiple type parameters, use the where keyword multiple times:

public class MyDictionary<K, V>
 where K : IComparable<K> where V : ICloneable {
 //...
}

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